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Saturday, May 17, 2025

How do you calculate 1+2+3+4+5+6+7+8+9+10 quickly?

You can calculate the sum of 1+2+3++101 + 2 + 3 + \dots + 10 quickly using a well-known formula for the sum of an arithmetic series. The formula is:

Sum=n(n+1)2\text{Sum} = \frac{n(n+1)}{2}

where nn is the largest number in the series. In this case, n=10n = 10.

Plugging in the value of nn:

Sum=10(10+1)2=10×112=1102=55\text{Sum} = \frac{10(10+1)}{2} = \frac{10 \times 11}{2} = \frac{110}{2} = 55

So, the sum of 1+2+3++101 + 2 + 3 + \dots + 10 is 55.

Quick Explanation:

This formula works because the sum of the first and last number is the same as the sum of the second and second-to-last number, and so on. For example:

(1+10),(2+9),(3+8),=11,11,11,(1 + 10), (2 + 9), (3 + 8), \dots = 11, 11, 11, \dots

There are 5 such pairs, so the total sum is 5×11=555 \times 11 = 55.

Source: Some or all of the content was generated using an AI language model

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