Here’s why the result isn’t actually that astonishing.
We start with the sum of a geometric series (valid for |x|<1
∑∞n=0xn=11−x
Differentiating both sides gives
∑∞n=1nxn−1=1(1−x)2
and hence
∑∞n=1nxn=x(1−x)2
Going back to the original series, subtracting the first term gives
∑∞n=1xn=11−x−1=x1−x
If k
is some constant, we have
∑∞n=1kxn=kx1−x
and hence
∑∞n=1(k−n)xn=kx1−x−x(1−x)2=kx(1−x)−x(1−x)2
The ratio between these is
∑∞n=1(k−n)xn∑∞n=1nxn=kx(1−x)−xx=k(1−x)−1
Now, when x=110
and k=10
this becomes
∑∞n=110−n10n∑∞n=1n10n=10(910)−1=8
But a number expressed in decimal is just a particular kind of sum involving powers of ten:
0.123456789=1101+2102+⋯+9109=∑9n=1n10n
and, likewise,
0.987654321=∑9n=110−n10n
that is, these numbers are just the sums in the numerator and denominator, but truncated after 9
terms. That means that their ratio should be approximately 8, with a small amount of “error” resulting from truncating the sums. Nothing astonishing; just algebra and calculus.
Source: Some or all of the content was generated using an AI language model
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